6k^2+24=-26k

Solution for 6k^2+24=-26k equation:

6k^2+24=-26k

We move all terms to the left:

6k^2+24-(-26k)=0

We get rid of parentheses

6k^2+26k+24=0

a = 6; b = 26; c = +24;
Δ = b2-4ac
Δ = 262-4·6·24
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-10}{2*6}=\frac{-36}{12}
=-3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+10}{2*6}=\frac{-16}{12}
=-1+1/3
$